JEE Main 2023 — Biomolecules Question with Solution
From: JEE Main 2023 (Online) 6th April Morning Shift
Question
Match List I with List II
| LIST I Enzymatic reaction |
LIST II Enzyme |
||
|---|---|---|---|
| A. | Sucrose Glocuse and Fructose | I. | Zymase |
| B. | Glucose ethyl alcohol and CO | II. | Pepsin |
| C. | Starch Maltose | III. | Invertase |
| D. | Proteins Amino acids | IV. | Diastase |
Choose the correct answer from the options given below:
Choose an option
Show full solutionCorrect option: B
Correct answer
BA-III, B-I, C-IV, D-II
Step-by-step explanation
Let's match the enzymes with the corresponding reactions:
- The enzyme that catalyzes the hydrolysis of sucrose to glucose and fructose is invertase. So, A matches with III.
- The enzyme that catalyzes the conversion of glucose to ethyl alcohol and CO(_2) (a step in fermentation) is zymase. So, B matches with I.
- The enzyme that catalyzes the conversion of starch to maltose is diastase. So, C matches with IV.
- The enzyme that breaks down proteins into amino acids is pepsin. So, D matches with II.
So, the correct option is:
Option B A-III, B-I, C-IV, D-II
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This is a previous-year question from JEE Main 2023, covering the Biomolecules chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.