JEE Main 2018ChemistryBiomoleculesCarbohydrateseasyMCQ

JEE Main 2018Biomolecules Question with Solution

From: JEE Main 2018 (Offline)

Question

Glucose on prolonged heating with HI gives

Choose an option

Show full solutionCorrect option: B
Correct answer
Bn-Hexane

Step-by-step explanation

As HI is a strong reducing agent, it reduces all the aldehydes and ketones to acohol and alcohols are further reduce to alkanes.

JEE Main 2018 (Offline) Chemistry - Biomolecules Question 161 English Explanation

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About this question

This is a previous-year question from JEE Main 2018, covering the Biomolecules chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.