JEE Main 2023ChemistryCarboxylic Acid DerivativesHardMCQ

JEE Main 2023Carboxylic Acid Derivatives Question with Solution

JEE Main 2023 (01 Feb Shift 2)

Question

In a reaction

reagents ‘X’ and ‘Y’ respectively are:

Choose an option

Show full solutionCorrect option: A
Correct answer
ACH3CO2O/H+ and CH3OH/H+, 

Step-by-step explanation

When salicylic acid is heated with methyl alcohol, the carboxyl group of salicylic acid is esterified producing a strong-smelling liquid ester (methyl salicylate). Aspirin is prepared by chemical synthesis from salicylic acid, through acetylation with acetic anhydride.

 Hence, reagent 'Y' and 'X' respectively are: CH3OH/H+,  and CH3CO2O/H+.

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About this question

This is a previous-year question from JEE Main 2023, covering the Carboxylic Acid Derivatives chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.