JEE Main 2022ChemistryCarboxylic Acid DerivativesHardMCQ

JEE Main 2022 — Carboxylic Acid Derivatives Question with Solution

JEE Main 2022 (29 Jun Shift 2)

Question

In Friedel-Crafts alkylation of aniline, one gets:

Choose an option

Show full solutionCorrect option: D
Correct answer
Dpositively charged nitrogen at benzene ring.

Step-by-step explanation

Aniline does not undergo Friedel-crafts reaction due to salt formation with aluminium chloride, the Lewis acid, which is used as a catalyst, whereas aniline is a strong base. So, an acid-base reaction will take place. Thus, aniline reacts with AlCl3 to form a salt.

Due to the positive charge on the nitrogen atom (shows -I effect and it is meta directing), electrophilic substitution in the benzene ring is deactivated. Hence, the Friedel-Crafts reaction will not take place in aniline.

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About this question

This is a previous-year question from JEE Main 2022, covering the Carboxylic Acid Derivatives chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.