JEE Main 2024ChemistryChemical Bonding And Molecular StructureValence Bond TheoryeasyNumerical

JEE Main 2024Chemical Bonding And Molecular Structure Question with Solution

From: JEE Main 2024 (Online) 1st February Morning Shift

Question

The lowest oxidation number of an atom in a compound is -2 . The number of electrons in its valence shell is _______.

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Step-by-step explanation

When an atom has the lowest oxidation number of -2 in a compound, it means the atom has gained two electrons beyond its neutral state to achieve this oxidation state. This is because gaining electrons makes the oxidation number more negative. In a neutral atom, the electrons in the outermost shell are known as valence electrons, which play a crucial role in chemical reactions and bonding.

In the given compound , atom B has an oxidation state of -2, indicating it has gained two electrons. For an atom to gain two electrons to complete its octet implies that its neutral state had six valence electrons. Therefore, before gaining electrons, the atom B would have had six electrons in its valence shell to begin with. As it gains two more electrons, it reaches an oxidation number of -2, implying it now has a complete octet or eight electrons in its valence shell, but the original count of valence electrons in its neutral state was six.

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About this question

This is a previous-year question from JEE Main 2024, covering the Chemical Bonding And Molecular Structure chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.