JEE Main 2002 — Chemical Bonding And Molecular Structure Question with Solution

(a) AlH₃ + H^$$-$$ $$\to$$ AlH$${}_4^{-}$$

Steric number of AlH₃ is = $$\frac{1}{2}$$ [3 + 3] = 3

$$\therefore$$ AlH₃ is sp² hybridized.

Steric number of AlH$${}_4^{-}$$ = $$\frac{1}{2}$$ [3 + 4 +1] = 4

$$\therefore$$ AlH$${}_4^{-}$$ is sp³ hybridized.

(b) H₂O + H⁺ $$\to$$ H₃O⁺

Steric no of H₂O = $$\frac{1}{2}$$ (6+ 2) = 4

$$\therefore$$ H₂O s sp³ hybridized.

Steric no of H₃O⁺ = $$\frac{1}{2}$$ [ 8 + 3 $$-$$1] = 4

$$\therefore$$ H₃O⁺ s also sp³ hybridized.

(c) NH₃ + H⁺ $$\to$$ NH₄⁺

Steric no of NH₃ = $$\frac{1}{2}$$ [5 + 3] = 4

$$\therefore$$ hybridization of NH₃ is sp³

Steric number of NH₄⁺ = $$\frac{1}{2}$$ [5 + 4 $$-$$ ] = 4

$$\therefore$$ Hybridization of NH₄⁺ is sp³