JEE Main 2021 — Chemical Equilibrium Question with Solution
From: JEE Main 2021 (Online) 27th July Morning Shift
Question
PCl5 PCl3 + Cl2
Kc = 1.844
3.0 moles of PCl5 is introduced in a 1 L closed reaction vessel at 380 K. The number of moles of PCl5 at equilibrium is ______________ 103. (Round off to the Nearest Integer)
Kc = 1.844
3.0 moles of PCl5 is introduced in a 1 L closed reaction vessel at 380 K. The number of moles of PCl5 at equilibrium is ______________ 103. (Round off to the Nearest Integer)
Enter your answer
Show full solutionCorrect answer: 3
Correct answer
3
Step-by-step explanation
PCl5(g) PCl3(g) + Cl2(g) K2 = 1.844
t = 0 3moles
t = x x
Moles of PCl5 = 3 1.604 1.396
t = 0 3moles
t = x x
Moles of PCl5 = 3 1.604 1.396
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