JEE Main 2022 — Chemical Equilibrium Question with Solution
From: JEE Main 2022 (Online) 25th June Morning Shift
Question
The standard free energy change (G) for 50% dissociation of N2O4 into NO2 at 27C and 1 atm pressure is x J mol1. The value of x is ___________. (Nearest Integer)
[Given : R = 8.31 J K1 mol1, log 1.33 = 0.1239 ln 10 = 2.3]
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Show full solutionCorrect answer: -710
Correct answer
-710
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This is a previous-year question from JEE Main 2022, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.