JEE Main 2013 — Chemical Equilibrium Question with Solution
JEE Main 2013 (25 Apr Online)
Question
The ratio for the reaction
is:
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
For the reaction
$\begin{aligned}
& \mathrm{CO}(\mathrm{g})+\frac{1}{2} \mathrm{O}_2(g) \leftrightharpoons \mathrm{CO}_2(\mathrm{~g}) \\
& \Delta n_g=1-\left(1+\frac{1}{2}\right)=-\frac{1}{2}
\end{aligned}$
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This is a previous-year question from JEE Main 2013, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.