JEE Main 2022ChemistryChemical EquilibriumHardNumerical

JEE Main 2022 — Chemical Equilibrium Question with Solution

JEE Main 2022 (24 Jun Shift 2)

Question

PCl5 dissociates as PCl5g⇌PCl3g+Cl2g 5 moles of PCl5 are placed in a 200 litre vessel which contains 2 moles of N2 and is maintained at 600 K. The equilibrium pressure is 2.46 atm. The equilibrium constant Kp for the dissociation of PCl5 is___×10-3. (nearest integer) (Given: R=0.082 L atm K-1 mol-1; Assume ideal gas behaviour)

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Show full solutionCorrect answer: 1107
Correct answer
1107

Step-by-step explanation

PCl5   ⇌ PCl3+Cl25mole       -      -     Intial moles5-x           x        x      EquilibriumTotal number of moles=5+x+nN2=7+xAs number of moles of Nitrogen gas added is 2ntotal=PVRT=2.46X 2000.082X600=107+x=10x=3Kp=310x2.46310x2.46210x2.46=1107

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About this question

This is a previous-year question from JEE Main 2022, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.