JEE Main 2014ChemistryChemical EquilibriumMediumMCQ

JEE Main 2014 — Chemical Equilibrium Question with Solution

JEE Main 2014 (09 Apr Online)

Question

At a certain temperature, only 50% HI is dissociated into H2 and I2 at equilibrium. The equilibrium constant is :

Choose an option

Show full solutionCorrect option: D
Correct answer
D0.25

Step-by-step explanation

2HIg⇌H2g+I2gMoles1-αα2α2Concentration1-αVα2Vα2V

KC=H2I2HI2=α2Vα2V1-αV2

       ∴α=0.50α2=0.25

       =α241-α2=0.50×0.504×0.50×0.50=14

        K C = 0.25

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Chemical Equilibrium chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2014, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.