JEE Main 2019 — Chemical Equilibrium Question with Solution
From: JEE Main 2019 (Online) 12th April Evening Slot
Question
In which one of the following equilibria, Kp KC ?
Choose an option
Show full solutionCorrect option: B
Correct answer
B2C(s) + O2(g) ⇋ 2CO(g)
Step-by-step explanation
We know,
Kp = KC(RT)ng
Kp = KC when ng = 0
Kp KC when ng 0 and T 12 K
In this reaction, 2C(s) + O2(g) ⇋ 2CO(g)
ng = 1, so Kp KC
Kp = KC(RT)ng
Kp = KC when ng = 0
Kp KC when ng 0 and T 12 K
In this reaction, 2C(s) + O2(g) ⇋ 2CO(g)
ng = 1, so Kp KC
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This is a previous-year question from JEE Main 2019, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.