JEE Main 2019ChemistryChemical EquilibriumHardMCQ

JEE Main 2019 — Chemical Equilibrium Question with Solution

JEE Main 2019 (12 Apr Shift 2)

Question

In which one of the following equilibria, Kp≠Kc?

Choose an option

Show full solutionCorrect option: B
Correct answer
B2Cs+O2g⇌2COg

Step-by-step explanation

kp=kcRTΔng  
(i) 2HIg⇌H2g+I2g
Δng=1+1-2=0
So   kp=kc
(ii) 2NOg⇌N2g+O2g
Δng=2-2=0
So   kp=kc
(iii) NO2g+SO2g⇌NOg+SO3g
Δng=2-2=0
So   kp=kc
(iv) 2s+O2g⇌2COg
Δng=2-1=1
kp=kcRTΔn⇒kp=kcRT
kp>kc

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About this question

This is a previous-year question from JEE Main 2019, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.