JEE Main 2020ChemistryChemical EquilibriumEasyMCQ

JEE Main 2020 — Chemical Equilibrium Question with Solution

JEE Main 2020 (06 Sep Shift 2)

Question

The value of Kc us 64 at 800 K for the reaction

N2g+3H2g→2 NH3 g

The value of Kc for the following reaction is :

NH3 g→12 N2 g+32 H2 (g)

Choose an option

Show full solutionCorrect option: D
Correct answer
D1/8

Step-by-step explanation

N2g+3H2g⇌2NH3g

KC=NH32N2H23=64

For the reaction

NH3g⇌12N2g+32H2g

K'C=N21/2H23/2NH3=1KC=164=18

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About this question

This is a previous-year question from JEE Main 2020, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.