JEE Main 2020ChemistryChemical EquilibriumChemical Equilibrium Law Of Mass Action And Equilibrium ConstanteasyMCQ

JEE Main 2020Chemical Equilibrium Question with Solution

From: JEE Main 2020 (Online) 6th September Morning Slot

Question

For the reaction

Fe2N(s) + H2(g) ⇌ 2Fe(s) + NH3(g)

Choose an option

Show full solutionCorrect option: A
Correct answer
AKC = Kp(RT)1/2

Step-by-step explanation

To determine the correct relationship between the equilibrium constants and for the reaction:

First, consider the general relationship between and :

where is the change in the number of moles of gas between the products and the reactants, is the ideal gas constant, and is the temperature in Kelvin.

For the given reaction, calculate :

Moles of gas in products: NH3(g) = 1 mole

Moles of gas in reactants: H2(g) = 1.5 moles

Therefore:

Substitute this value into the equation relating and :

Rearrange to express :

Thus, the correct option is:

Option A:

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About this question

This is a previous-year question from JEE Main 2020, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.