JEE Main 2021ChemistryChemical EquilibriumMediumNumerical

JEE Main 2021 — Chemical Equilibrium Question with Solution

JEE Main 2021 (20 Jul Shift 1)

Question

2SO2( g)+O2( g)⇌2SO3( g)
In an equilibrium mixture, the partial pressures are
PSO3=43kPa;PO2=530 Pa and
PSO2=45kPa. The equilibrium constant
KP=_____×10-2. (Nearest integer)

Enter your answer

Show full solutionCorrect answer: 172
Correct answer
172

Step-by-step explanation

2SO2( g)+O2( g)=2SO3( g)
KP=pSO3( g)2pSO2g2×pO2( g)
=43×4345×45×0.530 
=172.28×10-2 kPa-1
≃172 × 10-2
Ans is 172

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Chemical Equilibrium chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.