JEE Main 2015ChemistryChemical EquilibriumMediumMCQ

JEE Main 2015 — Chemical Equilibrium Question with Solution

JEE Main 2015 (10 Apr Online)

Question

Gaseous N2O4 dissociates into gaseous NO2 according to the reaction N2O4g⇌2NO2g
At 300 K and 1 atm pressure, the degree of dissociation of N2O4 is 0.2. If one mole of N2O4 gas is contained in a vessel, then the density of the equilibrium mixture is:

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Show full solutionCorrect option: A
Correct answer
A3.11 g/L

Step-by-step explanation

N2O4⇌2NO21-α2α

Total moles at equilibrium =1-α+2α=1+α=1.2

Mavg for equilibrium mixture = 0.8×92+0.4×46 1.2  

= 76.67 g/mol

daverage =PMavgRT=1×76.670.082×300=76.6724.6

=3.11 gL-1

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About this question

This is a previous-year question from JEE Main 2015, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.