JEE Main 2024ChemistryChemical EquilibriumEasyMCQ

JEE Main 2024Chemical Equilibrium Question with Solution

JEE Main 2024 (31 Jan Shift 1)

Question

For the given reaction, choose the correct expression of KC from the following:

Fe3+aq+SCN-aq(FeSCN)2+aq

Choose an option

Show full solutionCorrect option: A
Correct answer
AKC=FeSCN2+Fe3+SCN-

Step-by-step explanation

The equilibrium constant of a chemical reaction (usually denoted by the symbol K) provides insight into the relationship between the products and reactants when a chemical reaction reaches equilibrium. For example, the equilibrium constant of concentration (denoted by Kc) of a chemical reaction at equilibrium can be defined as the ratio of the concentration of products to the concentration of the reactants, each raised to their respective stoichiometric coefficients. It is important to note that there are different types of equilibrium constants that provide relationships between the products and the reactants of equilibrium reactions in terms of different units.

Equilibrium Constant Formula

Keqb=KfKb=CcDdAaBb=Kc

Where Kc indicates the equilibrium constant measured in moles per litre.

KC=Products Reactants 

KC=FeSCN2+Fe3+SCN-

Hence, the answer is option A.

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About this question

This is a previous-year question from JEE Main 2024, covering the Chemical Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.