JEE Main 2026 — Chemical Kinetics Question with Solution
JEE Main 2026 (21 January Shift 2)
Question
Decomposition of A is a first order reaction at and is given by . In a closed 1 L vessel, 1 bar is allowed to decompose at . After 100 minutes, the total pressure was 1.5 bar. What is the rate constant of the reaction ?
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Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
For the reaction , initially pressure of A is 1 bar.
Initially: total pressure = 1 bar.
After 100 min: total pressure = 1.5 bar.
Using initial and final pressures, if x bar of A decomposes, then A becomes (1-x), B = x, C = x.
Total pressure = 1-x+x+x = 1+x = 1.5, so x = 0.5 bar.
For a first-order reaction: .
Using pressures instead:
min ≈ min
Initially: total pressure = 1 bar.
After 100 min: total pressure = 1.5 bar.
Using initial and final pressures, if x bar of A decomposes, then A becomes (1-x), B = x, C = x.
Total pressure = 1-x+x+x = 1+x = 1.5, so x = 0.5 bar.
For a first-order reaction: .
Using pressures instead:
min ≈ min
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This is a previous-year question from JEE Main 2026, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.