JEE Main 2023ChemistryCoordination CompoundsEasyMCQ

JEE Main 2023 — Coordination Compounds Question with Solution

JEE Main 2023 (11 Apr Shift 2)

Question

The magnetic moment is measured in Bohr Magneton (BM). Spin only magnetic moment of Fe in FeH2O63+ and FeCN63- complexes respectively is:

Choose an option

Show full solutionCorrect option: C
Correct answer
C5.92 B.M. and 1.732 B.M.

Step-by-step explanation

The spin only magnetic moment can be calculated as follows

μ=nn+2BM

n=Number of unpaired electrons

FeH2O63+=d5(High spin complex)=5.unpaired electrons
μ=5×7=35
=5.92 B.M.
FeCN63+=d5(Low spin complex)=1
μ=1×3=3
=1.732 B.M.

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About this question

This is a previous-year question from JEE Main 2023, covering the Coordination Compounds chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.