JEE Main 2025 — Coordination Compounds Question with Solution

The compound with the strongest oxidizing power among Mn₂O₃, TiO, and VO is Mn₂O₃. This conclusion is based on the standard electrode potential ($E^{\circ }$) value:

$E_{{\text{Mn}}^{+3}/{\text{Mn}}^{+2}}^{\circ }=+1.57\text{V}$

For Mn³⁺, the electronic configuration is $d^4$. The spin-only magnetic moment ($\mu$) is calculated as follows:

$\mu =\sqrt{n(n+2)}\text{BM}$

Where $n$ is the number of unpaired electrons. Here, $n=4$:

$\mu =\sqrt{4(4+2)}=\sqrt{24}\text{BM}$

This calculates to approximately 4.89 BM, which rounds to an integer value of 5 BM.