JEE Main 2021 — D And F Block Elements Question with Solution
From: JEE Main 2021 (Online) 25th July Evening Shift
Question
Number of electrons present in 4f orbital of Ho3+ ion is ____________. (Given Atomic No. of Ho = 67)
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Correct answer
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Step-by-step explanation
Ho = [Xe]4f116s2
Ho3+ = [Xe] 4f10
So number of e present in 4f is 10.
Ho3+ = [Xe] 4f10
So number of e present in 4f is 10.
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