JEE Main 2023Chemistryd and f Block ElementsMediumMCQ

JEE Main 2023d and f Block Elements Question with Solution

JEE Main 2023 (31 Jan Shift 1)

Question

Nd2+=______

Choose an option

Show full solutionCorrect option: B
Correct answer
B4f4

Step-by-step explanation

The atomic number of Neodymium (Nd) is 60. Its electronic configuration is Xe 4f4 6s2.

Now, by removing two electrons from the outermost shell 6s, Nd2+ ion is formed. Hence, electronic configuration of Nd2+ is Xe 4f4.

 

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About this question

This is a previous-year question from JEE Main 2023, covering the d and f Block Elements chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.