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JEE Main 2024 — Electrochemistry Question with Solution

JEE Main 2024 (31 Jan Shift 1)

Question

One Faraday of electricity liberates x×10–1 gram atom of copper from copper sulphate, x is______.

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Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

One Faraday of electricity means it is equivalent to one mole of electrons charge.

Cu2++2e–→Cu

2 Faraday →1 mol Cu

1 Faraday →0.5 mol Cu deposit

0.5 mol=0.5 g atom=5×10–1

x=5

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About this question

This is a previous-year question from JEE Main 2024, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.