JEE Main 2021 — Electrochemistry Question with Solution
From: JEE Main 2021 (Online) 20th July Evening Shift
Question
Potassium chlorate is prepared by electrolysis of KCl in basic solution as shown by following equation.
6OH + Cl ClO3 + 3H2O + 6e
A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. The value of x is ____________. (Nearest integer)
(Molar mass of KClO3 = 122.6 g mol1, F = 96500 C)
6OH + Cl ClO3 + 3H2O + 6e
A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. The value of x is ____________. (Nearest integer)
(Molar mass of KClO3 = 122.6 g mol1, F = 96500 C)
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Show full solutionCorrect answer: 1.311
Correct answer
1.311
Step-by-step explanation
Ans. (1)
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