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JEE Main 2024Electrochemistry Question with Solution

JEE Main 2024 (29 Jan Shift 2)

Question

A constant current was passed through a solution of AuCl4- ion between gold electrodes. After a period of 10.0 minutes, the increase in mass of cathode was 1.314 g. The total charge passed through the solution is ___×10-2 F. (Given atomic mass of Au=197)

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Correct answer
2

Step-by-step explanation

The half-cell reaction is,

Au3+ + 3e  Au

Given W = 1.314 g

Atomic mass of Au=197

When one Faraday of charge is passed through a circuit, then one equivalent of charge is deposited at the respective electrode.

WE= charge1 F

1.3141973=Q1F

Q=2×10-2 F

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About this question

This is a previous-year question from JEE Main 2024, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.