JEE Main 2022ChemistryElectrochemistryMediumNumerical

JEE Main 2022 — Electrochemistry Question with Solution

JEE Main 2022 (29 Jun Shift 2)

Question

The cell potential for the given cell at 298 K PtH2g,1 barH+aq‖Cu2+aqCus is 0.31 V. The pH of the acidic solution is found to be 3, whereas the concentration of Cu2+ is 10x M. The value of x is _________.

(Given: ECu2+/CuΘ=0.34 V and 2.303RTF=0.06 V)

Enter your answer

Show full solutionCorrect answer: 7
Correct answer
7

Step-by-step explanation

H2g+Cu2+aq.→2H+aq.+Cus

Applying nernst equation

Ecell=Ecell0-0.06nlogproductsReactants

Ecell=Cell potential=0.31VEcell0=0.34pH=3,Hence,H+=10-3

0.31=0.34-0.062logH+2Cu2+

Cu2+=10-7M

x=7

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About this question

This is a previous-year question from JEE Main 2022, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.