JEE Main 2022ChemistryElectrochemistryHardNumerical

JEE Main 2022 — Electrochemistry Question with Solution

JEE Main 2022 (28 Jun Shift 1)

Question

The solubility product of a sparingly soluble salt A2X3 is 1.1×10-23. If specific conductance of the solution is 3×10-5Sm-1, the limiting molar conductivity of the solution is x×10-3 S m2 mol-1. The value of x is

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Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

KspA2X3=1.1×10-23=110×10-25

Ksp=2233s5=110×10-25

4×27s5=110×10-25;  S=M=1×10-5

K=3×10-5Sm-1

λm=x×10-3Sm2 mol-1

λm=K×10-3M

=3×10-5×10-31×10-5=3×10-3Sm2 mol-1

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About this question

This is a previous-year question from JEE Main 2022, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.