JEE Main 2020ChemistryElectrochemistryMediumMCQ

JEE Main 2020 — Electrochemistry Question with Solution

JEE Main 2020 (04 Sep Shift 1)

Question


ECu2+|Cu0=+0.34 V
EZn2+|Zn0=−0.76 V
Identify the incorrect statement from the options below for the above cell:

Choose an option

Show full solutionCorrect option: B
Correct answer
BIf Eext>1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode

Step-by-step explanation

Ecell∘=ECu2+Cu∘−EZn2+Zn∘=1.1 V

So If E=1.1 V no electron will flow

At E>1.1 V cell act as electrolytic cell and electron will flow from Cu to Zn.

At E<1.1 V cell act as electrochemical so Zn dissolve and Cu deposit.

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About this question

This is a previous-year question from JEE Main 2020, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.