JEE Main 2020 — Electrochemistry Question with Solution
From: JEE Main 2020 (Online) 2nd September Evening Slot
Question
For the disproportionation reaction
2Cu+(aq) ⇌ Cu(s) + Cu2+(aq) at 298 K. ln K
(where K is the equilibrium constant) is
___________ × 10–1.
Given :
(
)
2Cu+(aq) ⇌ Cu(s) + Cu2+(aq) at 298 K. ln K
(where K is the equilibrium constant) is
___________ × 10–1.
Given :
(
)
Enter your answer
Show full solutionCorrect answer: 144
Correct answer
144
Step-by-step explanation
= -
= 0.52 – 0.16
= 0.36 V
At equilibrium, Ecell = 0
= ln K
ln K =
= = 14.4 = 144 10-1
= 0.52 – 0.16
= 0.36 V
At equilibrium, Ecell = 0
= ln K
ln K =
= = 14.4 = 144 10-1
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