JEE Main 2008 — Electrochemistry Question with Solution
From: AIEEE 2008
Question
Given = -0.72 V; = -0.42V, The potential for the cell Cr | Cr3+ (0.1M) || Fe2+ (0.01 M) | Fe is
Choose an option
Show full solutionCorrect option: A
Correct answer
A0.26 V
Step-by-step explanation
From the given representation of the cell, can be found as follows.
Nernst - Equ.
Hence option (d) is correct answer.
Nernst - Equ.
Hence option (d) is correct answer.
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This is a previous-year question from JEE Main 2008, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.