JEE Main 2022ChemistryHaloalkanes and HaloarenesMediumMCQ

JEE Main 2022Haloalkanes and Haloarenes Question with Solution

JEE Main 2022 (26 Jul Shift 1)

Question

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : Experimental reaction of CH3Cl with aniline and anhydrous AlCl3 does not give o and p-methylaniline.

Reason R : The -NH2 group of aniline becomes deactivating because of salt formation with anhydrous AlCl3 and hence yields m-methyl aniline as the product.

In the light of the above statements, choose the most appropriate answer from the options given below

Choose an option

Show full solutionCorrect option: C
Correct answer
CA is true, but R is false.

Step-by-step explanation

Under the Friedel Craft Reaction condition, the aniline (a Lewis base) binds to the electrophile AlCl3 (a Lewis acid) to give a coordination complex (a salt). Then, the positive charge on the nitrogen is electron withdrawing, and it pulls the electron density of the aromatic ring by -I effect. It therefore, deactivates the ring for further alkylation reactions. Finally, the complex precipitates out of the reaction mixture and the alkylation reaction is not observed.

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About this question

This is a previous-year question from JEE Main 2022, covering the Haloalkanes and Haloarenes chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.