JEE Main 2026 — Hydrocarbons Question with Solution
JEE Main 2026 (22 January Shift 1)
Question
The cycloalkene on bromination consumes one mole of bromine per mole of and gives the product in which ratio is 3:1. The percentage of bromine in the product is %. (Nearest integer) (Given : molar mass in )
Enter your answer
Show full solutionCorrect answer: 66
Correct answer
66
Step-by-step explanation
A cycloalkene (X) undergoes bromination with 1 mole of Br₂, consuming 2 moles of Br atoms (addition to the double bond).
The product (Y) has C:Br ratio of 3:1.
With 2 Br atoms present, the number of C atoms is 2 × 3 = 6.
Therefore, product Y has composition C₆H₁₂Br₂ with molar mass
g/mol.
Percentage of Br = (2 × 80 / 244) × 100 = (160 / 244) × 100
= 65.57%, which rounds to 66% (nearest integer).
The product (Y) has C:Br ratio of 3:1.
With 2 Br atoms present, the number of C atoms is 2 × 3 = 6.
Therefore, product Y has composition C₆H₁₂Br₂ with molar mass
g/mol.
Percentage of Br = (2 × 80 / 244) × 100 = (160 / 244) × 100
= 65.57%, which rounds to 66% (nearest integer).
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Hydrocarbons chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2026, covering the Hydrocarbons chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.