JEE Main 2025 — Hydrocarbons Question with Solution

Molecular formula of isomeric hydrocarbon $\to C_9{H}_{12}$ - Negative Baeyer's test

Baeyers test is given by compounds that contain readily active carbon-carbon double bond.

So, in a negative Baeyer's test, there is no readily active c = c.

Compounds that give negative Baeyer's test are alkanes and aromatic compounds.

C${}_9$H${}_{12}$ compound is not an alkane

(Alkane general formula C${}_n$H${}_{2n+2}$)

Hydrocarbons with the formula C${}_9$H${}_{12}$ are considered as aromatic and isomers of substituted benzene rings.

The possible isomers of C${}_9$H${}_{12}$ are

From these, total number of the isomers with four different non-aliphatic substitution sites are 2

Four positions (1,2,3,4) are different. So, it contain four different non-aliphatic substitution sites.	Four position (1,2,3,4) are different. So, it contain four different non-aliphatic substitution sites.	Four position (1,2,3,4) are not different. So, it contain four different non-aliphatic substitution sites.