JEE Main 2021 — Hydrogen Question with Solution
From: JEE Main 2021 (Online) 25th July Morning Shift
Question
At 298.2 K the relationship between enthalpy of bond dissociation (in kJ mol1) for hydrogen (EH) and its isotope, deuterium (ED), is best described by :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Enthalpy of bond dissociation (kJ/mole) at 298.2 K
For, Hydrogen = 435.88
For, Deuterium = 443.35
For, Hydrogen = 435.88
For, Deuterium = 443.35
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This is a previous-year question from JEE Main 2021, covering the Hydrogen chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.