JEE Main 2023 — Hydrogen Question with Solution

Here, the ${\mathrm{H}}_2{\mathrm{O}}_2$ act as the reducing agent, as the $\mathrm{Cl}$ has +1 oxidation state of in $\mathrm{NaOCl}$ and after reaction with the ${\mathrm{H}}_2{\mathrm{O}}_2$, in the presence of the acid, it reduces the $\mathrm{Cl}$ in $\mathrm{NaOCl}$ to ${\mathrm{Cl}}^{-}$ having -1 oxidation state.

So, as $\mathrm{Cl}$ oxidation state decreases from the +1 to -1 oxidation state, hence the ${\mathrm{H}}_2{\mathrm{O}}_2$ is acting as the reducing agent.