JEE Main 2020ChemistryIonic EquilibriumEasyNumerical

JEE Main 2020 — Ionic Equilibrium Question with Solution

JEE Main 2020 (07 Jan Shift 1)

Question

Two solutions, A and B, each of 100L was made by dissolving 4g of NaOH and 9.8g of H2SO4 in water, respectively. The pH of the resultant solution obtained from mixing 40L of solution A and 10L of solution B is ____________. (log 2=0.3)

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Show full solutionCorrect answer: 10.6
Correct answer
10.6

Step-by-step explanation

MH2SO4⇒9.898×100=10-3
MNaOH⇒440×100=10-3
=40×10-3-10×10-3×250=2050×10-3
OH-=25×10-3=4×10-4
pOH=4-log4=3.4pH=14-3.4=10.6


 

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About this question

This is a previous-year question from JEE Main 2020, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.