JEE Main 2019ChemistryIonic EquilibriumHardMCQ

JEE Main 2019Ionic Equilibrium Question with Solution

JEE Main 2019 (10 Apr Shift 1)

Question

Consider the following statements
(a) The pH of a mixture containing 400 mL of 0.1 M H2SO4 and 400 mL of 0.1 M NaOH will be approximately 1.3.
(b) Ionic product of water is temperature dependent.
(c) A monobasic acid with Ka=10-5 has a pH=5 . The degree of dissociation of this acid is 50% .
(d) The Le Chatelier's principle is not applicable to common-ion effect.
The correct statements are:

Choose an option

Show full solutionCorrect option: D
Correct answer
D(a), (b)  and  (c)

Step-by-step explanation

Strong acid + Strong base mixture
n H2SO4>n[NaOH] So H+ will be more
H+=2×0.1×400-0.1×400800=0.05
pH=-logH+=-log0.05=1.3
(b) The ionic product of water is temperature dependent
(c) HCOOHH++HCOO- (weak acid)
ka=Cα21-α
ka=Cα.α1-α
ka=H+α1-α
10-5=10-5×α1-α
1-α=α
α=12=0.5
(d) Le-Chatelier’s Principle in applicable on Common Ion Effect

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About this question

This is a previous-year question from JEE Main 2019, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.