JEE Main 2022ChemistryIonic EquilibriumMediumMCQ

JEE Main 2022 — Ionic Equilibrium Question with Solution

JEE Main 2022 (25 Jul Shift 2)

Question

Ka1,Ka2 and Ka3 are the respective ionization constants for the following reactions a,b and c.

(a) H2C2O4⇌H++HC2O4-

(b) HC2O4-⇌H++HC2O42-

(c) H2C2O4⇌2H++C2O42-

The relationship between Ka1, Ka2 and Ka3 is given as

Choose an option

Show full solutionCorrect option: D
Correct answer
DKa3=Ka1×Ka2

Step-by-step explanation

H2C2O4⇌H++HC2O4-Ka1

H2C2O4-⇌H++C2O42-Ka2

H2C2O4⇌2H++C2O42-   Ka3

On adding equation 1 and equation 2 we get equation 3. So, Ka3=Ka1×Ka2.

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About this question

This is a previous-year question from JEE Main 2022, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.