JEE Main 2021ChemistryIonic EquilibriumHardMCQ

JEE Main 2021Ionic Equilibrium Question with Solution

JEE Main 2021 (20 Jul Shift 2)

Question

A solution is 0.1M in Cl- and 0.001M in CrO42-.
Solid AgNO3 is gradually added to it Assuming that the addition does not change in volume and Ksp(AgCl)=1.7×10-10M2 and
KspAg2CrO4=1.9×10-12M3.

Select correct statement from the following:

Choose an option

Show full solutionCorrect option: D
Correct answer
DAgCl will precipitate first as the amount of Ag+ needed to precipitate is low.

Step-by-step explanation

i Ag+ required to ppt AgCls

Ksp=IP=Ag+Cl-=1.7×10-10

Ag+=1.7×10-9

ii Ag+ required to ppt Ag2CrO4s

Ksp=IP=[Ag+]2CrO4-2=1.9×10-12

Ag+=4.3×10-5

Ag+ required to ppt AgCl is low so AgCl will ppt 1st.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Ionic Equilibrium chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.