JEE Main 2022 — Ionic Equilibrium Question with Solution
From: JEE Main 2022 (Online) 25th June Evening Shift
Question
The Ksp for bismuth sulphide (Bi2S3) is 1.08 1073. The solubility of Bi2S3 in mol L1 at 298 K is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A1.0 1015
Step-by-step explanation
Ksp = (2s)2(3s)3 = 108s5
108s5 = 108 × 10–75
s = 1.0 × 10–15 mol/L
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This is a previous-year question from JEE Main 2022, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.