JEE Main 2019ChemistryIonic EquilibriumHardMCQ

JEE Main 2019 — Ionic Equilibrium Question with Solution

JEE Main 2019 (10 Jan Shift 1)

Question

A mixture of 100 m mol of Ca(OH)2 and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. What is the mass of calcium sulphate formed and the concentration of OH- in resulting solution, respectively? (Molar mass of CaOH2, Na2SO4 and CaSO4 are 74, 143  and 136 g mol-1, respectively; Ksp of CaOH2 is 5.5×10-6)

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Show full solutionCorrect option: C
Correct answer
C1.9 g, 0.28 mol L-1

Step-by-step explanation



Mass of CaSO4=14×1361000=1.9 g

CaSO4=14×1361000=1.9 g

OH-=28100=0.28 M

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About this question

This is a previous-year question from JEE Main 2019, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.