JEE Main 2021 — Ionic Equilibrium Question with Solution
From: JEE Main 2021 (Online) 16th March Morning Shift
Question
Two salts A2X and MX have the same value of solubility product of 4.0 1012. The ratio of their molar solubilities i.e. = __________. (Round off to the Nearest Integer)
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Show full solutionCorrect answer: 50
Correct answer
50
Step-by-step explanation
For A2X
\matrix{ {{A_2}X} & \to & {2{A^ + }} & {{X^{2 - }}} \cr {} & {} & {2{S_1}} & {{S_1}} \cr }
S1 = 104
for MX
\matrix{ {MX} & \to & {{M^ + }} & {{X^ - }} \cr {} & {} & {{S_2}} & {{S_2}} \cr }
S2 = 2 106
so,
\matrix{ {{A_2}X} & \to & {2{A^ + }} & {{X^{2 - }}} \cr {} & {} & {2{S_1}} & {{S_1}} \cr }
S1 = 104
for MX
\matrix{ {MX} & \to & {{M^ + }} & {{X^ - }} \cr {} & {} & {{S_2}} & {{S_2}} \cr }
S2 = 2 106
so,
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