JEE Main 2023ChemistryIonic EquilibriumHardNumerical

JEE Main 2023 — Ionic Equilibrium Question with Solution

JEE Main 2023 (29 Jan Shift 2)

Question

The volume of HCl, containing 73g L-1, required to completely neutralise NaOH obtained by reacting 0.69 g of metallic sodium with water, is _____ mL. (Nearest Integer)

(Given : molar Masses of Na,Cl,O,H are 23,35.5,16 and 1g mol-1 respectively)

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Show full solutionCorrect answer: 15
Correct answer
15

Step-by-step explanation

Mole of NaOH=0.6923=3×10-2

2Na+2H2O⟶2NaOH+H2

Number of moles of Na = Number of moles of NaOH

NaOH + HCl → NaCl + H2O

Moles of HCl = moles of NaOH

⇒ (Molarity × V)HCl = Number of moles of NaOH

⇒ 7336.5 × 1 × V = 0.03

⇒V = 15 × 10-3 Lit

⇒ V = 15 mL 

 

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About this question

This is a previous-year question from JEE Main 2023, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.