JEE Main 2014ChemistryIonic EquilibriumEasyMCQ

JEE Main 2014 — Ionic Equilibrium Question with Solution

JEE Main 2014 (19 Apr Online)

Question

Zirconium phosphate [Zr3(PO4)4] dissociates into three zirconium cations of charge​ +4 and four phosphate anions of charge -3. If molar solubility of zirconium phosphate is denoted by s and its solubility product by Ksp then which of the following relationship between s and Ksp is correct ​?

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Show full solutionCorrect option: D
Correct answer
D S = K sp / 6 9 1 2 1 / 7

Step-by-step explanation

In the saturated solution of

Zr 3 PO 4 4 + aq ⇌ 3 Zr 4 + 3 S molar + 4 PO 4 3 - 4 S molar

K sp = Zr 4 + 3 PO 4 3 - 4 = 3 S 3 4 S 4

= 2 7 × 2 5 6 × s 7 = 6 9 1 2   S 7

S = K sp 6 9 1 2 1 / 7

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About this question

This is a previous-year question from JEE Main 2014, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.