JEE Main 2019 — Ionic Equilibrium Question with Solution
From: JEE Main 2019 (Online) 12th January Evening Slot
Question
If Ksp of Ag2CO3 is 8 10–12, the molar solubility of Ag2CO3 in 0.1 M AgNO3 is -
Choose an option
Show full solutionCorrect option: B
Correct answer
B8 10–10 M
Step-by-step explanation
8 1012 = (2s + 0.1)2 s
s 102 = 8 1012
s = 8 1010
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This is a previous-year question from JEE Main 2019, covering the Ionic Equilibrium chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.