JEE Main 2022Chemistryp Block Elements (Group 13 & 14)MediumMCQ

JEE Main 2022p Block Elements (Group 13 & 14) Question with Solution

JEE Main 2022 (25 Jul Shift 1)

Question

The geometry around boron in the product 'B' formed from the following reaction is

BF3+NaH450 KA+NaF

A+NMe3B

Choose an option

Show full solutionCorrect option: B
Correct answer
Btetrahedral

Step-by-step explanation

2BF3+6NaHB2H6A+6NaF

In this reaction hydride ions replace the fluoride ions. and diborane is formed, which is a Lewis acid due to incomplete octet. It breaks symmetrically with bases like tertiary amines.

B2H6+2Me3N2Me3N+BBH3- 

In this product geometry around Boron will be tetrahedral. And it will have sp3 hybridisation.

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About this question

This is a previous-year question from JEE Main 2022, covering the p Block Elements (Group 13 & 14) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.