JEE Main 2021 — Redox Reactions Question with Solution
From: JEE Main 2021 (Online) 27th July Evening Shift
Question
10.0 mL of 0.05 M KMnO4 solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is _________ 102 g/L.
(Round off to the nearest integer)
(Round off to the nearest integer)
Enter your answer
Show full solutionCorrect answer: 1575
Correct answer
1575
Step-by-step explanation
neq KMnO4 = neq H2C2O4 . 2H2O
or,
Conc. of oxalic acid solution = 0.125 M
= 0.125 125 g/L = 15.75 g/L
= 1575 102 g/L
or,
Conc. of oxalic acid solution = 0.125 M
= 0.125 125 g/L = 15.75 g/L
= 1575 102 g/L
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