JEE Main 2021ChemistryRedox ReactionsMediumNumerical

JEE Main 2021 — Redox Reactions Question with Solution

JEE Main 2021 (27 Jul Shift 2)

Question

10.0 mL of 0.05 M KMnO4 solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is ........ ×10-2 g/L. (Round off to the nearest integer)

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Show full solutionCorrect answer: 1575
Correct answer
1575

Step-by-step explanation

neqKMnO4=neqH2C2O4·2H2O

or, 10×0.051000×5=10×M1000×2

∴ Conc. of oxalic acid solution =0.125M

=0.125×126 g/L=15.75 g/L

=1575×10-2 g/L

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About this question

This is a previous-year question from JEE Main 2021, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.