JEE Main 2019ChemistryRedox ReactionsMediumMCQ

JEE Main 2019 — Redox Reactions Question with Solution

JEE Main 2019 (12 Apr Shift 1)

Question

Given:
Co3++e-→Co2+;E°=+1.81V
Pb3++2e-→Pb2+;E°=+1.67V
Ce4++e-→Ce3+;E°=+1.61V
Bi3++3e-→Bi;E°=+0.20V
Oxidizing power of the species will increase in the order:

Choose an option

Show full solutionCorrect option: B
Correct answer
BBi3+<Ce4+<Pb4+<Co3+

Step-by-step explanation

Higher the value of ERed0; higher will be its oxidizing power.

Hence correct order is Bi+3<Ce+4<Pb+4<Co+3

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About this question

This is a previous-year question from JEE Main 2019, covering the Redox Reactions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.